Question

Calculate the number of oxalic acid molecules in
100 ml of 0.01 M oxalic acid solution.
​

Answer 1

Answer:

Normality=molarity×basicity for acids/acidity for bases

Here N=0.02 & as oxalic acid is a dibasic acid so it will have a badicity of 2.

M=0.02÷2=0.01

Molarity=no of moles × volume(lit)

M=0.01×0.1=0.001moles

As 1 mole= 6.603×10*23=6.6×10*23×0.001= 6.6×10*20.

Explanation:

Answer 2

The number of oxalic acid molecules in given amount of oxalic acid solution is $6.022\times 10^{-26}$

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

We are given:

Molarity of oxalic acid solution = 0.01 M

Volume of solution = 100 mL

Putting values in above equation, we get:

$0.01M=\frac{\text{Moles of oxalic acid}\times 1000}{100}\\\\\text{Moles of oxalic acid}=\frac{(0.01\times 100)}{1000}=0.001mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, 0.001 moles of compound contains $(0.001\times 6.022\times 10^{23})=6.022\times 10^{-26}$ number of molecules

Learn more about mole concept and molarity:

https://brainly.in/question/4533997

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