Question

Calculate the number of oxygen atom in 0.10 moles of Na2co3,10 H2o

Answer 1

Number of Oxygen atoms:

$0.10 mol Na_{2}CO_{3}. 10 H_{2}O$×$\frac{13mol O}{1 mol Na_{2}CO_{3}. 10H_{2}O}$×$\frac{6.022 * 10^{23} atoms O}{1 mol O}$

= 7.83 x$10^{23} atoms O$