calculate the number of oxygen atoms and its weight in 50g of CaCO3
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Gram molecular mass of CaCO3 = 40 + 12 + 48 = 100 g
Gram molecular mass of oxygen = 32 g
Therefore
32 g of oxygen is present in 100 g of CaCO3
⇒ 16 g of oxygen is present in 50 g of CaCO3
In 32 g of oxygen, 6.02*10^23
Therefore in 16 g of oxygen, no of atoms present = 3.011*10^23
Gram molecular mass of oxygen = 32 g
Therefore
32 g of oxygen is present in 100 g of CaCO3
⇒ 16 g of oxygen is present in 50 g of CaCO3
In 32 g of oxygen, 6.02*10^23
Therefore in 16 g of oxygen, no of atoms present = 3.011*10^23
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