Calculate the number of oxygen atoms in 0.20 mole of Na2CO3.10H2O
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heyy mate here is ur ans....✌❤❤
⏩Molar mass of Na2CO3.10H2O = 46 + 12 + 48 + 36 = 122u
⏩First of all we have to find given mass
⏩So no. of moles = given mass/molar mass
0.20 = x/122
x = 122 × 0.20
x = 24.4
⏩Now we have to find no. of atoms
= given mass/molar mass × avogadro no.
= 24.4/122 × 6.022×10^23
= .2 × 6.022×10^23
= 12.044 × 10^24
⏩so no. of atoms = 12.044×10^24
Hope it helps u....if it did plzz mark me brainliest....thanks...✌❤❤
(If u have any doubt regarding this u can ask me)
⏩Molar mass of Na2CO3.10H2O = 46 + 12 + 48 + 36 = 122u
⏩First of all we have to find given mass
⏩So no. of moles = given mass/molar mass
0.20 = x/122
x = 122 × 0.20
x = 24.4
⏩Now we have to find no. of atoms
= given mass/molar mass × avogadro no.
= 24.4/122 × 6.022×10^23
= .2 × 6.022×10^23
= 12.044 × 10^24
⏩so no. of atoms = 12.044×10^24
Hope it helps u....if it did plzz mark me brainliest....thanks...✌❤❤
(If u have any doubt regarding this u can ask me)
OS13:
Ok change it
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