Question

Calculate the number of oxygen atoms present in 150g of oxygen gas and 150g of ozone​

Answer 1

56.42 × 10²³ atoms of Oxygen

18.78 × 10²³ atoms of Ozon

Explanation:

Given: mass of O₂ and O₃ = 150 g,

molecular weight of O₂ = 16 g, molecular weight of O₃ = 48g

Number of moles:

For O₂ = 150/16

            = 9.37 moles

For O₃ = 150/48

            = 3.12 moles

Number of atoms present in

O₂ = 9.37 × 6.022 × 10²³ = 56.42 × 10²³ atoms

O₃ = 3.12 × 6.022 × 10²³ = 18.78 × 10²³ atoms