Question

calculate the number of particles for 23 g of sodium atoms ​

Answer 1

Answer:

There are 6.02*10^23 atoms in each mole (Avagadro no.) That is x moles * avagadro no. According to that, in 23 grams of sodium we have 6.02*10^23 atoms of Na.

Step-by-step explanation:

Hope it will help you

Answer 2

Step-by-step explanation:

Given : Mass of sodium atom is $23$ g.

To find : The number of particles of sodium atom.

Formula used :

Number of particles of any compound = no. of moles of that compound × Avogadro number ($N_A$)

Number of moles(n) of compound 'x'

$n=\frac{W_x}{MM_x}$

W is the given mass and MM is the molar mass of compound 'x'.

• Calculation for no. of moles

For finding the number of particles of sodium atom firstly we have to find the no. of moles of sodium atom.

For the no. of moles we require mass(W) and molar mass(MM) of sodium. so the mass of sodium(W) is given to us as,

$W=23g$

and as we know the molar mass(MM) of sodium is

$MM=23g/mol$

No. of moles are;

$n=\frac{W_x}{MM_x}$

   $=\frac{23g}{23g/mol}$

   $=1mol$

In this way we get the no. of moles of sodium is 1 mole.

• Calculation for number of particles of sodium

By using formula,

Number of particles of Sodium = no. of moles of sodium × Avogadro number ($N_A$)

we know the no. of moles of sodium and value of Avogadro number  $(N_A)$ is,

$N_A=6.023*10^{23} mol^{-1}$

so the number of particles of sodium are,

Number of particles of Sodium $=1mol*6.023*10^{23}mol^{-1}$

                                                   $=6.023*10^{23}$ particles.

Hence we get the no. of particles of sodium atom are $6.023*10^{23}$.