Question

Calculate the number of particles present in 0.5moles of Nitric acid.​

Answer 1

Answer:

Explanation: 0.5 mole of Nitrogen

   1 mole of N=14 gram

    0.5 mole N=0.5×14

=7gram

=  

2

1

​  

mole

                                   =  

2

1

​  

×6.022×10  

23

atoms

                                    =3.011×10  

23

atoms.

 

(c) 8 gram O =?

     16 gram of O =1mole

     1 gram of O =  

16

1

​  

mole

      8 gram of O =  

16

1

​  

×8=  

2

1

​  

 

                          =  

2

1

​  

×6.022×10  

23

atoms

=3.011×10  

23

atoms.

 

 Same as in O,S mole of nitrogen.

Answer 2

$\huge {\red{\boxed{\tt{\red{14\;grams}}}}}$