Question

calculate the number of particles present in 52g of carbon -6 molecule? ​

Answer 1

no. of moles in one carbon molecule

$= \frac{52}{12} \\ = \frac{13}{3}$

no. of moles in 6 carbon molecules

$= 6 \times \frac{13}{3} \\ = 26moles$

again,

No. of particles

$= 26 \times 6.023 \times {10}^{23} \\ = 1.56598 \times {10}^{25}$

Here's your answer dude hope it helps.

Answer 2

Answer:

Hey dear,

Explanation:

We know that 1 molecule of Helium is equal to 4 gram.  

So we can write that 1 mole = 4 g  

Or, 4 g = 1 mole = 6.022 X 10 ²³ atoms  

So, 1 g = ¼ mole = (6.022 X 10 ²³)/4 atoms  

52 g = ¼ X 52 mole = [(6.022 X 10 ²³)/4] X 52 atoms  

       = 13 mole = 7.8286 X 10 ²³  

Thus 52 grams of He has 13 molecules.

Hope it helps!!