Question

Calculate the number of photons emitted in 1 hour by 100 W sodium lamp. Wavelength of light emitted is 5890 angstrom​

Answer 1

${\blue{\underline{\underline{\bold{\huge{Given:-}}}}}}$

P = 100 W

&

t = 1 hour or 3600sec

lambda = 5890 A°

${\blue{\underline{\underline{\bold{\huge{Solution:-}}}}}}$

As we know,

E = P* t

= 100 * 3600

= 360000 J

Here, we know ___

1 A° = 10^-10 m

Then,

Lambda = 5890 × 10^-10 m

Hence,

E = nhc/lambda

➯ n = E* lambda /hc

➯ n = (360000)*5890 × 10^-10 / (6.626 × 10^-34) *(3 ×10^8)

➯ n = 1.0667*10^24 photons

${\huge{\mathcal{\pink{Hope \ It's \ Helpful.!!!}}}}$

Answer 2

Answer:

{\blue{\underline{\underline{\bold{\huge{Given:-}}}}}}

Given:−

P = 100 W

&

t = 1 hour or 3600sec

lambda = 5890 A°

{\blue{\underline{\underline{\bold{\huge{Solution:-}}}}}}

Solution:−

As we know,

E = P* t

= 100 * 3600

= 360000 J

Here, we know ___

1 A° = 10^-10 m

Then,

Lambda = 5890 × 10^-10 m

Hence,

E = nhc/lambda

➯ n = E* lambda /hc

➯ n = (360000)*5890 × 10^-10 / (6.626 × 10^-34) *(3 ×10^8)

➯ n = 1.0667*10^24 photons

{\huge{\mathcal{\pink{Hope \ It's \ Helpful.!!!}}}}Hope It

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s Helpful.!!!