Question

Calculate the number of sodium ions in 53g Na2CO3

Answer 1

Answer:

Explanation:

Molar mass of sodium carbonate=106g

No. of moles =given mass /molar mass

53/106=0.5 moles of na2co3

1 mol contains 6.022*10^23 ions of na

0.5 mol of na is present in given compound

3.011*10^23 ions of na

Answer 2

Explanation:

no.of na ions from Na2Co3

to find Na ions , we have to calculate the moles present in C,O and Na

Na=23×2=Na=53÷46

= 1.15 moles

C= 12g= 53÷12

=4.41 moles

O = 16g ×3=48=53÷48

=1.10 moles

moles of C + moles of O - moles of Na

4.41+1.10- 1.15

= 5.51- 1.15

4.31

so 4.31 no. of sodium ions are present in 53 f of Na2CO3