Calculate the number of unit cell in 24 g Mg whichcrystallises in hcp lattice. (NA = 6.0 x 1023particles/mole)
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Explanation:
The molar mass of NaCl is⇒23+35.5=58.5 g.
Thus, 58.5 g of NaCl corresponds to 1 mole of NaCl and contains 6.023×10
23 molecules.
One unit cell of NaCl (fcc structure) has 4 NaCl molecules. Hence, 1 mole of NaCl will contain 4
6.023×10
23≈1.5×10
23 unit cells.
The number of unit cells in 58.5 g of NaCl is nearly 1.5×10^23
.
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