Calculate the number of unit cell in 24 g Mg which
crystallises in hcp lattice. (NA = 6.0 x 1023
particles/mole)
Answers
the number of unit cells is 1.0038 × 10²³.
Given : 24g Mg crystallises in hexagonal closed packed lattice.
To find : The number of unit cells.
solution : given weight of Mg = 24 g
atomic weight of Mg = 24 g/mol
so, no of moles of Mg = 24/24 = 1 mol
now no of atoms of Mg in 24 g = no of moles of Mg × Avogadro's number
= 1 × 6.023 × 10²³
= 6.023 × 10²³
as Mg crystallises in hexagonal closed packed lattice.
we know, no of atoms per unit cell of hcp = 6
so, no of unit cells = no of atoms in 24g Mg/no of atoms in a unit cell
= 6.023 × 10²³/6
= 1.0038 × 10²³
Therefore the number of unit cells is 1.0038 × 10²³.
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Answer:This may help you
Explanation:
Moles of NaCl=
58.5
10
Number of molecules of NaCl=
58.5
10
×6.023×10
23
In one unit cell 4 molecules of NaCl are present.
Number of unit cells =
58.5
10×6.023×10
23
×
4
1
=
58.5
1.5
×10
24