Calculate the number of unit cell in 58.5 g of sodium chloride
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atomic mass of sodium=23 g
this means 23 g has no. of toms=6.022 multiply 1023
therefore 58.5 g has no. of atoms= 6.022 x 1023/23 x58.5
therefore no. of atoms in a unit cell of bcc structure=2
there fore no. of unit cell which contains no. of atoms= 6.022 x 1023 x 58.5/23x2
you wil get the answer.
this means 23 g has no. of toms=6.022 multiply 1023
therefore 58.5 g has no. of atoms= 6.022 x 1023/23 x58.5
therefore no. of atoms in a unit cell of bcc structure=2
there fore no. of unit cell which contains no. of atoms= 6.022 x 1023 x 58.5/23x2
you wil get the answer.
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