Question

Calculate the number of unpaired electrons in the following gaseous ions: Mn³⁺, Cr³⁺, V³⁺ and Ti³⁺. Which one of these is the most stable in aqueous solution?

Answer 1

Answer:

Explanation:

unpaired electrons in Mn3+, Cr3+, V3+ and Ti3+ respectively are 4, 3, 2, 1

Most stable in aqueous solution is Mn3+

Please see the fig. for detail explanation

Answer 2

Manganese ion is Most Stable.

Explanation:

We know that Stability of an Ion is directly proportional to the number of electrons in d- Sub-shell

• $Mn^+^3 = [Ar] 3 d^4$
• $Cr^+^3 = [Ar]3d^3$
• $V^+^3 = [Ar] 3d^2$
• $Ti^+^3 = [Ar] 3d^1$

Therefore, Most stable ion in Aqueous medium is Mn^+^3