Which one of the following does not exist? (i) XeOF₄ (ii) NeF₂ (iii) XeF₂ (iv) XeF₆
Answers
answer : NeF₂ doesn't exist
explanation : NeF₂ ⇔Ne²+ + 2F- , for formation of NeF₂ , two electrons are lost by Neon and gained by fluorine. but you know as well, Neon is inert gas. of course Xe is also a inert gas. but ionisation enthalpy of Ne is comparably larger than that of Xe. it has require larger amount of energy to remove electron from stable state. while Xe can form, XeOF₄, XeF₂ , XeF₆ etc.. because size of Xe is large and so, it has tendency to loss electrons from its stable state too.
in simple way, NeF₂ doesn't exist because the sum of first and 2nd ionisation enthalpies of Ne are much larger than that of Xe. as a result F₂ can oxidise Xe into Xe²+ , Xe⁴+ and Xe^6+ but cannot oxidize Ne to Ne²+.
Answer:
NeF2 does not exist
I hope it will help you