Question

calculate the number of valence and non valence electron present in 5.6 ml of a SO2 gas

Answer 1

we have to calculate the number of Valence and non Valence electrons present in 5.6 ml of a SO₂ gas.

Solution : first find number of molecules in 5.6 ml of SO₂ gas.

no of molecules = no of moles × Avogadro's number

= (5.6/22400) × 6.023 × 10²³

= 1/4000 × 6.023 × 10²³

= 1.50575 × 10²⁰

total no of electrons in one SO₂ molecule = 16 + 8 + 8 = 32

no of valence electrons in one SO₂ molecule = 6 + 6 + 6 = 18

so, no of non Valence electrons = 32 - 18 = 14

now in 1.50575 × 10²⁰ molecules of SO₂, no of valence electrons = 18 × 1.50575 × 10²⁰

= 27.1035 × 10²⁰

= 2.71035 × 10²¹

in 1.50575 × 10²⁰ molecules of SO₂ , no of non Valence electrons = 14 × 1.50575 × 10²⁰

= 21.0805 × 10²⁰

= 2.10805 × 10²¹