calculate the total ions and charge present in 4.2 gram of nitride
Answers
Nitride ion is a stable ion, meaning it has 8 valence electrons. The no of moles of nitride ion in 4.2g is 4.2/14=0.3 mol. So the no of valence electrons is equal to 8x0.3xNa, where Na is avogadros no. whose value is (6.022x10^23). ... 42 grams contains 3×5=15+1 gained electron, total 16 electrons ..
Explanation:
Given mass = 4.2g
Molar mass of N3^- (azide ion) = 14*3 = 42
Therefore, No. Of moles of azide ion = given
Mass/molecular mass = 4.2/42 0.1 moles
No. Of valence electron in one nitrogen atom = 5
No. Of valence electrons in azide ion (N=N=N) is = (5*3) + 1 = 16 electrons
Therefore, total no. Of valence electron in 4.2g of azide (N3^-) ion = no. Of moles of azide ion * no. Of valence electrons in one azide ion *
Avogadro's constant
=0.1* 16* 6.022*10^23
=1.6* 6.022*10^ 23
=9.6352* 10^23 valence electron