Calculate the number of valence electrons in 4.2 g of N−3 ion.
1.2.1NA
2.4.2NA
3.1.6NA
4.3.2NA
plz give me the answer fast
Answers
Answered by
4
Explanation:
Molecular wt of N3−=3×14=42 g
One ion of N3− has valence electrons = 3×5+1=16
42 g N3−=NA N3− ion
valence electrons in NA ions = 16NA (where NA = Avogadro's number)
So, 1 g of N3− will have valence electrons = 16NA/42
therefore,4.2g of N3− ion will have valence electrons = 16NA×4.2/42=1.6NA.
Option C is correct.
Hope This will help you
Answered by
1
Answer:
3. 1.6NA
Explanation:
I think this is correct answer
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