Question

calculate the number of water molecule present in one drop of water which weighs 0.18g​

Answer 1

Answer:

hi

your answer is here !

Explanation:

number of moles,n = w/M

w= 0.18 g

M of H2O= 18 g

∴n = 0.18/18 = 0.01

1 mole contains 6.023×10²³ molecules

∴0.01 mole contains (6.023×10²³)×0.01 = 6.023×10^21 molecules

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Answer 2

Hi mate

Question:

Calculate the number of water molecules present in one drop of water which weights 0.18g.

Solution

Mass of water = 0.18g

$No \: Of \: Mole = Mass \div Molar \: Mass$

= 0.18/18

= 0.01 Mole

$No.of.molecules = No.of.Moles × Avagadros Number$

= 0.01 × 6.023 × 10²³

= 0.06023 ×10²³

= 6.023 × 10²¹

Therefore, 6.023 × 10²¹ molecules is your answer.

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