Question

calculate the number of water molecule present in one drop of water which weights 0.18 g in


please answer me...then i will follow you.​

Answer 1

Answer:

w= 0.18 g

M of H2O= 18 g (mass)

∴n = 0.18/18 = 0.01 (moles)

1 mole contains 6.023×10²³ molecules

∴0.01 mole contains (6.023×10²³)×0.01 = 6.023×10^21 molecules

Hope this helps u.....