calculate the of magnesium required to react with 292 g of hydrochloric acid.
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Answer:
Magnesium reacts with hydrochloric acid according to the equation: Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g) This demonstration can be used to illustrate the characteristic reaction of metals with acid, a single replacement reaction, or to demonstrate the generation of hydrogen gas.
Magnesium and hydrochloric acid react according to the chemical equation: Mg + 2HCl => MgCl2 + H2.....
Explanation:
Mg(s) + 2HCl(aq) --> MgCl2(aq)+ H2(g) The ratio of Mg to HCl is 2 to one. You used 0.1 mole of HCl in all three flasks. All Mg and HCl used because the mole ratio is just right. Mg is the excess reactant HCl is the limiting reactant All the HCl reacts but there is 1.2 g of leftover Mg....Mark Brainlist Selected my Question
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