Question

calculate the of NH3 produced if 2.0×10^3g dinitrogen reacts with 1.0×10^3gm of dihydrogen. will any of the two reactant remain unreactant?

Solve it guys.....

Answer 1

N2 + 3H2 -> 2NH3

1 mole of N2 will react with 3 moles of H2

moles = given mass / molar mass

so, moles of H2 =

1.0×10^3g / 2g = 500 moles of H2

and moles of N2 =

2.0×10^3g / 28g = 71.43 moles of N2

As 1 mole of N2 will react with 3 moles of H2

so, 71.43 moles of N2 will react with

3/1 * 71.43 moles of H2

= 214.28 moles of H2

So, all N2 has undergone in the reaction

so, 500 - 214.28 moles of H2 will reamain unreacted

= 285.72 moles of H2 is unreacted

= 285.72 * 2 gm of H2

= 571.44 g of H2 will remain unreacted .