calculate the of NH3 produced if 2.0×10^3g dinitrogen reacts with 1.0×10^3gm of dihydrogen. will any of the two reactant remain unreactant?
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N2 + 3H2 -> 2NH3
1 mole of N2 will react with 3 moles of H2
moles = given mass / molar mass
so, moles of H2 =
1.0×10^3g / 2g = 500 moles of H2
and moles of N2 =
2.0×10^3g / 28g = 71.43 moles of N2
As 1 mole of N2 will react with 3 moles of H2
so, 71.43 moles of N2 will react with
3/1 * 71.43 moles of H2
= 214.28 moles of H2
So, all N2 has undergone in the reaction
so, 500 - 214.28 moles of H2 will reamain unreacted
= 285.72 moles of H2 is unreacted
= 285.72 * 2 gm of H2
= 571.44 g of H2 will remain unreacted .
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