Two year ago a father has five times as old as his son. two years layer his age will be 8 more than three timesthe age of son . find the present age of both
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Let present age of son be x years
and present age of father be y years
______________________________
2 years ago ;
son's age = x - 2
father's age = y - 2
but a/q ;
y - 2 = 5 ( x - 2 ) = 5x - 10
or, 5x - y = 8 _______________(i)
______________________________
Two years later ;
son's age = x + 2
father's age = y + 2
but a/q ;
y + 2 = 8 + 3 ( x + 2 )
or, y + 2 = 8 + 3x + 6 = 3x + 14
or, 3x - y = -12 ________________(ii)
_______________________________
Subtracting eqn (ii) from eqn (i) ; we get
2x = 20
or, x = 20 / 2 = 10 (son's age)
y = 3x + 12 = 3×10 + 12 = 42 (father's age)
and present age of father be y years
______________________________
2 years ago ;
son's age = x - 2
father's age = y - 2
but a/q ;
y - 2 = 5 ( x - 2 ) = 5x - 10
or, 5x - y = 8 _______________(i)
______________________________
Two years later ;
son's age = x + 2
father's age = y + 2
but a/q ;
y + 2 = 8 + 3 ( x + 2 )
or, y + 2 = 8 + 3x + 6 = 3x + 14
or, 3x - y = -12 ________________(ii)
_______________________________
Subtracting eqn (ii) from eqn (i) ; we get
2x = 20
or, x = 20 / 2 = 10 (son's age)
y = 3x + 12 = 3×10 + 12 = 42 (father's age)
Answered by
0
Hi friend,
# Age of father is 42 and son is 10
➡Solution :-
Let, the age of father is X and the age of son is Y
Let's Start :-
➡Given in the question ;-
x-2=5(y-2)
Or, x-5y= -10+2
Or, x-5y = -8
Or, x = 5y-8
Or, x+2 = 3(y+2)+8
Or, x-3y = 6+8-2
Or, 5y-8-3y = 12
Or, 2y = 12 + 8
Or , y = 20/2
Or, y= 10
➡Therefore, X = 5y-8...............(ii)
Or, x = 50-8
Or, x = 42
So, the age of father is 42 and the age of son is 10
_____________________________
Thanks !!
Be brainly !!!✌
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