Question

Calculate the osmoic pressure in pascals exerted by a solution prepared by dissolving
1.0g of polymer of molar mass 185000 in 450 mL of water at 37°C.​

Answer 1

Explanation:

Volume of water, V= 450 mL = 0.45 L

Temperature, T = (37 + 273)K = 310 K

Number of moles of the polymer,

n = 1 / 185000 mol

We know that:

Osmotic pressure,

= 1/185000 mol X 1/0.45L X 8.314 X 103 Pa L K-1mol-1 X 310K

= 30.98 Pa = 31 Pa (approximately)

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Answer 2

Thus, Osmotic pressure = 30.95 Pa