Question

Calculate the osmotic pressure at300k of a 5 percent aqueous solution of a glucose R=0.0821 liter atm

Answer 1

Answer : The osmotic pressure will be, 6.836 atm

Explanation :

Formula used :

$\pi =iCRT\\\\\pi=i\times \frac{w\times 1000}{M\times V}RT$

where,

i = Van't Hoff factor

For non-electrolyte i = 1 (always) and glucose is a non-electrolyte.

$\pi$ = osmotic pressure

C = concentration

R = solution constant

T = temperature

w = mass of glucose

M = molar mass of glucose = 180.156 g/mole

V = volume of solution

As we are given, 5 % aqueous solution of a glucose that means 5 grams of glucose present in 100 ml of solution.

So, mass of glucose = 5 g

Volume of solution = 100 ml

Now put all the given values in the above formula, we get:

$\pi=1\times \frac{5g\times 1000}{180.156g/mole\times 100ml}\times (0.0821L.atm/mole.K)\times (300K)$

$\pi=6.836atm$

Therefore, the osmotic pressure will be, 6.836 atm