Calculate the osmotic pressure in pascals exerted by a solution
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It is given that:
Volume of water, V= 450 mL = 0.45 L
Temperature, T = (37 + 273)K = 310 K
Number of moles of the polymer,
n = 1 / 185000 mol
We know that:
Osmotic pressure, = 22/7=n /V. RT
= 1/185000 mol X 1/0.45L X 8.314 X 103 Pa L K-1mol-1 X 310K
= 30.98 Pa = 31 Pa (approximately)
Answered by
0
Answer:
It is given that:
Volume of water, V= 450 mL = 0.45 L
Temperature, T = (37 + 273)K = 310 K
Number of moles of the polymer,
n = 1 / 185000 mol
We know that:
Osmotic pressure, = 22/7=n /V. RT
= 1/185000 mol X 1/0.45L X 8.314 X 103 Pa L K-1mol-1 X 310K
= 30.98 Pa = 31 Pa (approximately)
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