Question

Calculate the threshold frequency of the metal from which

Answer 1

Given λ = 6800 amgstrom or 6800x 10-10 m = 6.8 x 10-7m

C = 3 x 108 m/s

Also λ = c/v or v = c/ λ Therefore putting the values in the equation, we get

=3 x 108 / 6.8 x 10-7m = 4.41 x 1014 s-1

Hence, work function (W0) of the metal = hν0

= (6.626 × 10–34 Js) (4.41 × 1014 s–1)

= 2.922 × 10–19 J

Answer 2

Answer:

Given λ = 6800 amgstrom or 6800x 10-10 m = 6.8 x 10-7m

C = 3 x 108 m/s

Also λ = c/v or v = c/ λ Therefore putting the values in the equation, we get

=3 x 108 / 6.8 x 10-7m = 4.41 x 1014 s-1

Hence, work function (W0) of the metal = hν0

= (6.626 × 10–34 Js) (4.41 × 1014 s–1)

= 2.922 × 10–19 J