Question

Calculate the osmotic pressure of 0.2 m glucose solution at 300 k

Answer 1

Pv=inrt ...

Then .. it can be written as p =imrt ... Here I=1 ...

So p =60r. Is the osmotic pressure ..

Hope u understand ..

Answer 2

The osmotic pressure of 0.2 m glucose solution at 300 K is 5 atm

Explanation:

$\pi =CRT$

= osmotic pressure  = ?

C= concentration in Molarity = 0.2 M

R= solution constant  = 0.0821 Latm/Kmol

T= temperature =300 K

Putting in the values we get:

$\pi=0.2mol/L\times 0.0821Latm/Kmol\times 300K$

$\pi=5atm$

Osmotic pressure of 0.2 m glucose solution at 300 K is 5 atm

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