Question

calculate the osmotic pressure of a solution containing 1g of glucose per 100ml of solution at 25 degree celsius nm^-2.Molecular mass of glucose=180 (R=8.3141 J mol^-1 K^-1) this is from class 12 plz answer....give only relavent answers plz..

Answer 1

Answer:

osmotic pressure is 1.23

Explanation:

To find the osmotic pressure,we need find concentration term first.

molarityof solution,M=n÷v

=weight/molecularweight×1/V

=1/180×100/1000

= 1/1800

= 0.0005

and.temperature is converted to Kelvin

(273+25=298k)

osmotic pressure (π)=CRT

=0.0005×8.3141×298

=1.23atm