Calculate the osmotic pressure of a solution containing 3.42 gram of sucrose in 1 litre of water at 400 kelvin
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Dear student,
● Answer -
π = 0.3284 atm
● Explanation -
# Given -
W = 3.42 g
M = 342 g
T = 400 K
V = 1 L
# Solution -
Applying
π = n × R × T / V
π = 3.42/342 × 0.0821 × 400 / 1
π = 0.3284 atm
Therefore, osmosit pressure of solution is 0.3284 atm.
Hope this helped to clear your concepts.
Thanks for asking..
● Answer -
π = 0.3284 atm
● Explanation -
# Given -
W = 3.42 g
M = 342 g
T = 400 K
V = 1 L
# Solution -
Applying
π = n × R × T / V
π = 3.42/342 × 0.0821 × 400 / 1
π = 0.3284 atm
Therefore, osmosit pressure of solution is 0.3284 atm.
Hope this helped to clear your concepts.
Thanks for asking..
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