Math, asked by TheLoneWolf2264, 1 year ago

What is the sum of the coefficient in the expansion of (3+2x)^99?

Answers

Answered by somi173
10

Answer:

The sum of Coefficients in the expansion of (3+2x)^99 equal to 2^99.

Note: This is the sum of ONLY Binomial Coefficients.

Step-by-step explanation:

An algebraic expression consisting of two terms is called a Binomial.

It is also called a Binomial Expression.

The expression given in the question is (3+2x)^99.

We can compare it with (a+b)^n.

The sum of Coefficients in the expansion of (a+b)^n equal to 2^n.

So

The sum of Coefficients in the expansion of (3+2x)^99 equal to 2^99.

Note: This is the sum of ONLY Binomial Coefficients.

Answered by carissagpalmon
0

Answer:

1.57772181x10^69

Step-by-step explanation:

(2+3)^99-(3)^99=1.57772181x10^69

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