calculate the osotomic pressure of a solution prepared by dissolving 0.025g of k2so4 in 2l water at300k, assuming that the dissolved k2so4 is completely dissociated. (r=0.081l atm k-1mol-1; molar mass of k2so4= 174g mol-1)
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Answer:
1.76 x 10-3
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=> Osmotic pressure = 0.0017 ≈ 0.002 atm
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