Question

calculate the oxidation no of element in Bao2​

Answer 1

Answer:

exception is in effect here, because BaO2 is a peroxide consisting of Ba2+ and O22− ions. The oxidation number of Ba is +II, and the oxidation number of each of the oxygens in the peroxide anion is -I. This fits with the charge of the peroxide anion (2×−1=−2), and as BaO2 is a neutral compound, the sum of all oxidation numbers is 0. Moreover, there are even more exceptions to the rule of thumb cited above, for example, the superoxide radical anion O2− with a fractional oxidation numer of −12, or the dioxygenyl cation O2+ with a formal oxidation number of +12 for each oxygen.

In contrast to peroxides, "simple ionic compounds" of oxygen are oxides, which contain the anion O2−. The charge of the oxide anion is 2−, so the oxidation number of oxygen in those compounds is -II

Answer 2

Answer:

+2

The oxidation number of Ba is +2, and the oxidation number of each of the oxygens in the peroxide anion is -I. This fits with the charge of the peroxide anion (2×−1=−2), and as BaO2 is a neutral compound, the sum of all oxidation numbers is 0.