Calculate the oxidation no. of P in PH3 and H3PO4.
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Here's the answer you are looking for
Let us assume that the oxidation number of P is x.
Note:
♦The oxidation number of a molecule or compound is always zero.
♦The oxidation number of H is +1.
♦The oxidation number of O is always -2.
So now let's find out the value of x in PH3
Here,
x+ 3(+1) = 0
x + 3 = 0
x = -3
So in PH3 the oxidation number of P is –3.
In H3PO4,
3(+1) + x + 4(-2) = 0
3 + x - 8 = 0
x - 5 = 0
x = +5
So the oxidation number of P in H3PO4 is +5
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let us assume that the oxidation number of P is x.
Note:
♦The oxidation number of a molecule or compound is always zero.
♦The oxidation number of H is +1.
♦The oxidation number of O is always -2.
So now let's find out the value of x in PH3
Here,
x+ 3(+1) = 0
x + 3 = 0
x = -3
So in PH3 the oxidation number of P is –3.
In H3PO4,
3(+1) + x + 4(-2) = 0
3 + x - 8 = 0
x - 5 = 0
x = +5
So the oxidation number of P in H3PO4 is +5
★★ HOPE THAT HELPS ☺️ ★★
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