Find the sum of all the factors of 48 that are multiples of 6? i need it urgent...plzz explain the answer...:""))
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First find all the factors of 48.
Factors of 48 ⇒ 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Now, find out the multiples of 6 from this set of numbers.
The multiples of 6 are 6, 12, 24, 48.
Sum of the factors of 48 which are multiples of 6
Now, there are 10 factors of 48, but in this set of numbers, 4 numbers are multiples of 6. So, the multiples of 6 in this given situation are also the factors of 48.
Hence,
the sum of the factors of 48, that are the multiples of 6 is:
6 + 12 + 24 + 48 = 90
So, the sum is 90.
Very simple, of course.
Hope this may help you.
If you have some doubt, you can ask me in the comments.
Factors of 48 ⇒ 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Now, find out the multiples of 6 from this set of numbers.
The multiples of 6 are 6, 12, 24, 48.
Sum of the factors of 48 which are multiples of 6
Now, there are 10 factors of 48, but in this set of numbers, 4 numbers are multiples of 6. So, the multiples of 6 in this given situation are also the factors of 48.
Hence,
the sum of the factors of 48, that are the multiples of 6 is:
6 + 12 + 24 + 48 = 90
So, the sum is 90.
Very simple, of course.
Hope this may help you.
If you have some doubt, you can ask me in the comments.
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