Question

calculate the oxidation number of cr in cr2o3 and s in H2So4​

Answer 1

Answer:

cr= 3

MArk me as a brainleast

Answer 2

Answer:

Oxidation number of $Cr$ in $Cr_{2} O_{3}$ is +3.

Oxidation number of $S$ in $H_{2}SO_{4}$ is +6.

Explanation:

Cr₂O₃

The overall charge on the compound is zero.

The oxidation number of one $Cr$ is assumed to be $x$ and the oxidation number of one $O$ is -2.

The oxidation number of $Cr$ can be calculated by-

$2x + (-2)(3) = 0$

$2x = +6$

$x = +3$

The oxidation of $Cr$ is +3.

H₂SO₄

The overall charge on the compound is zero.

The oxidation number of one $S$ is assumed to be $x$, the oxidation number of one $O$ is -2 and the oxidation number of $H$ +1.

The oxidation number of $S$ can be calculated by-

$2(+1) + x + (-2)(4) = 0$

$+2 + x - 8 = 0$

$x - 6 = 0$

$x = +6$