calculate the oxidation number of Mn KMnO4
k (+1) o (+2)
Answers
Answered by
0
oxidation no of kmnO4 in acidic region is 5, in neutral (less basic) is 3&in alkaline is 1
Answered by
3
imagine mn=x
so
x+1(+1)+4(-2)=o
x=6-1
so mn oxidation no. is +5
so
x+1(+1)+4(-2)=o
x=6-1
so mn oxidation no. is +5
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