Question

calculate the oxidation number of N in NaNo2​

Answer 1

+1 x N x 2 (-2)

N -4+1=0

N-3=0

N= +3

Answer 2

The oxidation number of nitrogen in $NaNO_2$ is +3

Explanation:

Oxidation number is the number that is assigned to the element when it gains or looses electrons.

If an element gains electron, it will attain a negative oxidation number and if the element looses electrons, it will attain a positive oxidation number.

We are given a chemical compound having formula $NaNO_2$

We take the oxidation state of nitrogen atom be 'x'.

Oxidation state of sodium atom = +1

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of nitrogen atom:

$+1+x+2(-2)=0\\\\x=+3$

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