Question

please please please please please please please please please please answer

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Answer 1

firstly

volume of hemisphere=2/3πr^3

V=(2/3)*3.14*14*14*14

V=(2/3)*3.14*2744

V=5744.11 cm^3

main concept of this sum:

now volume of the sand will remain same no matter in what object it is kept

so volume of cone=5744.11

(1/3)πr^2h=5744.11

(1/3)*Area of base*h=5744.11

(you know that area of base of cone will be π*r^2)

Area of base=5744.11*3/7

A=2461.7 which is nearly equal to

A=2462 cm^2

hence area of base of cone is 2462 cm^2

hope this helps :))

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Answer 2

Therefore, the area of the ground occupied by the circular base of heap of sand is 2464 sq.cm