calculate the oxidation number of p in H3 PO 4
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H3PO4 = 3(1) + x + 4(-2)= 0 where x= o.n of p
3 + x - 8 = 0
x = 5
Thus oxidation number of P in H3PO4 is 5
3 + x - 8 = 0
x = 5
Thus oxidation number of P in H3PO4 is 5
manthan7445:
pls mark the answer brainliest
Answered by
1
3 x 1x p x 4(-2)=0
3 x p x-8=0
p-5= 0
p =+5
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