Question

calculate the oxidation number of p in H3P2O7

Answer 1

The charge of H2P2O7 is -1. 
And, therefore,
Oxidation number of Hydrogen is +1.
and for Oxygen, it is -2.
H3 gives, +3.
O7 gives -14.

Therefore, 3+2x-14=-1.
2x=10.
Therefore, x=+5.

Therefore,

the Oxidation number of P in H3P2O7 is,
+5.
Thank you.
Hope this will help you.

Answer 2

The oxidation number of p in H3P2O7 is +5.

• H3P2O7 is an oxo acid of phosphorous and is written as (H3P2O7)-.
• So, it has a charge of -1.
• It is known as diphosphate trihydrogen.
• Oxoacids are those compounds in which the central atom is bonded with one oxygen atom and one OH group.
• The oxidation state of hydrogen is +1 and the oxidation state of oxygen is -2(negative because oxygen is the most electronegative atom).
• Let the oxidation state of phosphorous be x.
• The oxidation state of H3P2O7 = 3 × 1 + 2 × x + 7 (-2) = -1
• Now, 3 + 2x -14 = -1
• 2x -11 = -1
• 2x = -1 + 11 = 10
• x = 10/2
• x = +5

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