calculate the oxidation number of s in NaHSO4
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Answered by
3
Answer:
oxidation state of S ie sulphur is -4
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14
Answer:
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Explanation:
oxidation number of Na is +1
oxidation number of H is +1
oxidation number of O is -2 but for O4 it is (4 × -2) = -8
and the oxidation number of the compound is zero
then oxidation number of S be taken as X
+1 +1 +X -8 = 0
+2 + X - 8 = 0
-6 + X = 0
X = +6
So oxidation number of S is +6
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