Calculate the Oxidation number of Sulphur in S2O82- ion.
Answer- +6
mrOogway:
Please write the ion in proper way, use subscript and superscript
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Hey dear,
● Answer -
O.S. = +6
● Explanation -
[Refer to diagram for structure]
- Let x be O.S. of sulphur in (S2O8)2-.
- There are total 8 O atoms, of which 2 involve in peroxide linkage with OS -1 and remaining 6 O atoms bearing OS -2.
Total charge on compound -
2×x + 2(-1) + 6(-2) = -2
2x - 14 = -2
2x = 12
x = +6
Therefore, OS of S in (S2O8)2- is +6.
Hope this helps you...
● Answer -
O.S. = +6
● Explanation -
[Refer to diagram for structure]
- Let x be O.S. of sulphur in (S2O8)2-.
- There are total 8 O atoms, of which 2 involve in peroxide linkage with OS -1 and remaining 6 O atoms bearing OS -2.
Total charge on compound -
2×x + 2(-1) + 6(-2) = -2
2x - 14 = -2
2x = 12
x = +6
Therefore, OS of S in (S2O8)2- is +6.
Hope this helps you...
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