calculate the parts per million for solution in which 2×10°^-7 kg calcium bicarbonate is dissolved in 2 litters solution.
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Explanation:
Molar mass of CaCO3 = 100g
Mass of CaCO3 = 10g
Moles of CaCO3 = Mass of solute/ Molar mass of solute = 10/100 = 0.1mol
Mass of solvent = Mass of solution - Mass of solute = 1000 - 10 = 990g or 0.99 kg
Molality = Number of moles of solute / Mass of solvent in Kg
Molality = 0.1/0.99 = 0.1010 m
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Answer:
Explanation:
Molar mass of CaCO3 = 100g
Mass of CaCO3 = 10g
Moles of CaCO3 = Mass of solute/ Molar mass of solute = 10/100 = 0.1mol
Mass of solvent = Mass of solution - Mass of solute = 1000 - 10 = 990g or 0.99 kg
Molality = number of moles of solute / Mass of solvent in Kg
Molality = 0.1/0.99 = 0.1010 m
Explanation:
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