calculate the percentage composition in terms of mass of solution obtained by mixing 300 gram of 25% and 400 gram of a 40% solution by mass
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Answered by
93
According to question,
300g of 25% solution contains solute = (300 x 25) / 100 = 75g
&
400g of 40% solution contains solute = (400 x 40) / 100 = 160g
Total solute = 75 + 160 = 235g
As given in the question, total solution =300 + 400 = 700g
Percentage of solute in the final solution = (235 x100) / 700 = 33.5%
Percentage of water in the final solution = 100 - 33.5 = 65.5%
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300g of 25% solution contains solute = (300 x 25) / 100 = 75g
&
400g of 40% solution contains solute = (400 x 40) / 100 = 160g
Total solute = 75 + 160 = 235g
As given in the question, total solution =300 + 400 = 700g
Percentage of solute in the final solution = (235 x100) / 700 = 33.5%
Percentage of water in the final solution = 100 - 33.5 = 65.5%
HOPE HELPFUL. plz mark me brainist . have a good night
Answered by
23
300g of 25% solution contains solute = (300 x 25) / 100 = 75g
&
400g of 40% solution contains solute = (400 x 40) / 100 = 160g
Total solute = 75 + 160 = 235g
As given in the question, total solution =300 + 400 = 700g
Percentage of solute in the final solution = (235 x100) / 700 = 33.5%
Percentage of water in the final solution = 100 - 33.5 = 65.5%
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