Physics, asked by aditya4sure, 1 year ago

Give the perfect reason for this answer (Answer is D) H.C.Verma

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Answered by dhruvsh

The derived formula for horizontal range on a plane is
R = u^2 sin 2theta / g
where,
u is the initial speed provided to the particle.
theta is the angle of projection.
and g is acceleration due to gravity.

Now, looking at the question to find the relationship between Range of A and Range of B.
We will need the speed and angles of projection.
we've been given the angles but we don't know the speeds of projection of both the particles. Hence we won't be able to find out the ranges of A and B and obviously not the relationship between them.

aditya4sure: But we can estimate that Range of A is u square/2g and range of B is u square/g... By that we can say Range of B is greater than range of A.... Something like that?

dhruvsh: ok but what if i see that the speed with which i throw A is larger than the speed with which i throw A

dhruvsh: the result you're telling is for the question when the speed of throwing both A and B is the same

dhruvsh: are you getting i

dhruvsh: it*?

aditya4sure: So.. it means that speed of throwing A and B is different... so we cannot get the result?

aditya4sure: I got that... Thanks!!

dhruvsh: exactly

dhruvsh: no prob bhai anytime

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