Question

Calculate
the percentage composition of -
1) Hydrogen in Ammonium Hydroxide.
2) Sulphur in Sulphur Trioxide.
[Atomic weight - N = 14,0 = 16,H=1, S=32]​

Answer 1

Amonium hydroxide = NH4OH

WEIGHT OF AMMONIUM HYDROXIDE = 23+4+16+1

=44

Weight of hydrogen / total weight ×100 = percentage of composition = 4/44 ×100

=100/11 = 9.090.....

=9 (aproximate )

9% or 9.090..%

sulphur tri oxide = SO3

WEIGHT OF SULPHUR TRIOXIDE=30+16×3

=78

WEIGHT OF SULPHUR / TOTAL WEIGHT = 30/78 ×100 =38.4...%

Answer 2

Answer:

hydrogen-9%

Sulphur-38.4%