calculate the percentage composition of copper 2 oxide (cu=64,o=16)
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Explanation:
Let the mass of mixture be 100 g.
Mass of CuO = x g
Mass of Cu
2
O=y g
So, mass of oxygen =
79.5
16x
+
143
16y
=12 g
Similarly, mass of Cu=
79.5
63.5x
+
143
127y
=88 g
so, x=8.65% and y=91.35%
Therefore, the nearest integer is 9%
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