calculate the percentage Composition of hydrogen in C6H12O6
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2
Answer:
not possible
Explanation:
impossible
Answered by
2
Answer:
53.3
Explanation:
Molecular mass of glucose C6H12O6 = 6 × 12 + 1 × 12 + 6 × 16 = 72 + 12 + 96 = 180 g %of carbon C in glucose = 72 /180 × 100 = 40 % of hydrogen H in glucose = 12/ 180 × 100 = 6.66 % of oxygen O in glucose = 96/ 180 × 100 = 53.3
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