Question

Calculate the percentage composition of K in Potassium nitrate.( K= 39, N=14, O=16)

Answer 1

Explanation:

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Answer 2

Answer:

The percentage composition of K in Potassium nitrate is $38.61$ %·

Explanation:

Potassium nitrate has a chemical formula of $KNO_3.$

Given that,

The atomic mass of potassium K $=$ $39$ g

The atomic mass of nitrogen N $=$ $14$ g

The atomic mass of oxygen O $=$ $16$ g

We know that the percentage composition of an element in a compound is defined as "the ratio of the mass of that element to the total mass of the one mole of that compound"·

That is,

    Percentage composition $=\ \ \frac{Mass\ of\ an\ element}{Total\ mass\ of\ the\ compound}$   ×  $100$%

Here,

The total mass of one mole of the compound $KNO_3$ is,

⇒ $KNO_3\ =\ 39\ +\ 14\ +\ (3\ *\ 16)\ =\ 101\ \frac{g}{mol}$

On substituting the values we get,

⇒ Percentage composition of K in $KNO_3$ $=\ \frac{39}{101} \ *\ 100$ %

⇒ Percentage composition of K in $KNO_3$   $=$   $38.61$ %

Therefore,

The percentage composition of K in Potassium nitrate is $38.61$ %·